Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole MCQ (Single Correct)

The electric field produced by a positively charged particle, placed in an xy-plane is 7.2 (4i + 3j) N/C at the point (3 cm, 3cm) and 100 N/C at the point (2 cm, 0).

A
The x-coordinate of the charged particle is –2cm.
B
The charged particle is placed on the x-axis.
C
The charge of the particle is 10 x 10 –12 C.
D
The electric potential at the origin due to the charge is 9V.

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(b, c, d)

At point (2cm, 0), field is along x-axis. It is possible only when the particle is situated on
x-axis. Its position is located by extending electric field direction from point (3cm, 3cm). The point at which this extension intersects x-axis, is the location of the charge. That is (–1cm, 0)

For point (2cm, 0), r = 3 cm, E = 100 N/C

Using, E = ⇒ Q = 10 x 10 –12 C

Potential at origin =

where, r = 1cm, Q = 10 x 10 –12 C

∴ V = 9V

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